Question

the electric field due to a uniformly charged non conducting solid sphere wuth charge 10C at a point 2cm from its centre will be (radius=1cm)​

Answer 1

Given ,

• Charge on a non conducting solid sphere (q) = 10 c
• Radius of non conducting solid sphere (R) = 1 cm

We know that ,

For outside point the electric field due to solid sphere or solid non conducting is given by

$\sf \large\fbox{E = \frac{k \times q}{ {(r)}^{2} } }$

Where ,

r = the distance between the point from the centre of sphere

Thus ,

$\sf \hookrightarrow E = \frac{9 \times {(10)}^{9} \times 10}{ {(2 \times {(10)}^{ - 2}) }^{2} } \\ \\ \sf \hookrightarrow E = \frac{9 \times {(10)}^{10} }{4 \times {(10)}^{ - 4} } \\ \\ \sf \hookrightarrow E = 2.25 \times {(10)}^{14} \: \: \: n/c \: \: or \: \: v/m$

Hence , the electric field is 2.25 × (10)^14 n/c or v/m