Question

the electric field due to point charge at a distance 6m from it is 630N/C .the magnitude of the charge is ?​

Answer 1

$e = kq \div {r}^{2}$

630= 9*10^9*q/6^2

q= 36*630/9*10^9

q= 2.5*10^-6

q= 2.5 micro coulomb