The electric field has a magnitude of 3.0 N/C at a distance of 60 cm from a point charge. What is the charge?
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Answered by
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Explanation:
we know that
E=1/4π€ Q/r^2
3=9×10^9×Q/(0.6)^2
q=12×10^11C
Answered by
0
Explanation:
We know that
E=1/4πC=Q rn 2
3=9×10n 9×Q1(0.6)^2
Q=12×10^11C
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