Question

The electric field in a certain region of a space is(5i^+4j^-4k^)× 10^5N c inverse. Calculate electric flux due to this field over an area of (2i^-j^)×10^-2m2

Answer 1

Electric field in a certain region of a space, E = $(5\hat{i}+4\hat{j}-4\hat{k})\times10^5 N/C$

surface area , A = $(2\hat{i}-\hat{j})\times10^{-2}m^2$

we know, electric flux is defined as number of electric lines of force passing through in a given area.

mathematically, electric flux is the dot product of electric field and surface area.

e.g,. electric flux = B.A

= $(5\hat{i}+4\hat{j}-4\hat{k})\times10^5 N/C.(2\hat{i}-\hat{j})\times10^{-2}m^2$

= (5 × 2 + 4 × -1 -4 × 0) × 10^(5 - 2) Nm²/C

= (10 - 4 ) × 10³ Nm²/C

= 6000 Nm²/C

hence, electric flux through given surface is 6000 Nm²/C.

Answer 2

I hope it will help you.