Physics, asked by siddhu000002017, 11 months ago


The electric field in a certain region of space is E -10'INC-1. How
much is the flux passing
through an area 'A' if it is a part of XY plane. XZ
plane, YZ plane, making an angle 30' with the axis​

Answers

Answered by dk6060805
6

Use \phi =  \overrightarrow{E}.\overrightarrow{A}

Explanation:

Given that,

\overrightarrow{E} = 10^4\widehat{i}\\

We have a relationship for Electric Flux,

\phi =  \overrightarrow{E}.\overrightarrow{A}

For xz plane,

\phi = 10^4 (i.j) = 0

For yz plane,

\phi = 10^4A

  • In electromagnetism, electric flux can be called as upon a surface known, the electric field being measured.

We know that,

It the electric field only which can't flow by itself.

  • If a point is taken some distance apart from any charge, then the field being described that causes the field, can be referred to as Electric Field.
Answered by bestwriters
11

The flux passing through an area is 5√3 × 10³ A

Explanation:

The electric flux is given by the formula:

F = E . A = EA cos Ф

Φ is the angle between plane area and axis

For XY plane ⇒ Φ = 0°

F = EA cos Ф = EA cos 0 = EA = 10⁴ A

For YZ plane ⇒ Φ = 90°

F = EA cos Ф = EA cos 90 = 0

For XZ plane ⇒ Φ = 90°

F = EA cos Ф = EA cos 90 = 0

The plane is making angle of 30° with axis, thus the flux is:

F = EA cos 30 = 10⁴A √(3/4)

∴ F = 5√3 × 10³ A

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