The electric field in a region is given as È = kr29. For a sphere of radius 'a', the total charge within it will be
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Answer:
ϕ=∮
E
.
ds
E
=
x
2
+y
2
a(x
i
^
+y
j
^
)
ϕ=∮
x
2
+y
2
a(x
i
^
+y
j
^
)
.
x
2
+y
2
+z
2
(x
i
^
+y
j
^
+k
z
^
)
ds
ϕ
net
=a∫
x
2
+y
2
x
2
+y
2
x
2
+y
2
+z
2
1
ds
ϕ
net
=
R
a
∫ds=
R
a
4πR
2
ϕ
net
=4πRa⇒
ε
0
q
=4πRa
q=4πε
0
Ra
Explanation:
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