The electric field in a region is given by ( ) 3 1 E 2i 3j 10 NC - Ù Ù = + ´
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The electric flux through a rectangular surface 10cm 20cm ´ held parallel to the y z - plane is
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Explanation:
Given:
Electric field strength, E⃗ =35E0iˆ+45 E0j⌢,
where E0 = 2.0×103 N/C
The plane of the rectangular surface is parallel to the y-z plane. The normal to the plane of the rectangular surface is along the x axis. Only 35E0i⌢ passes perpendicular to the plane; so, only this component of the field will contribute to flux.
On the other hand, 45E0j⌢ moves parallel to the surface.
Surface area of the rectangular surface, a = 0⋅2 m2
Flux,
ϕ=E⃗ .a⃗ =E×aϕ= (35×2×103)×(2×10−1) Nm2/Cϕ=0.24×103 Nm2/Cϕ=240 Nm2/C
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