Question

The electric field in a region is radially

outward and at a point is given by E = 250 r

V/m (where r is the distance of the point from

origin). Calculate the charge contained in a

sphere of radius 20 cm centred at the origin​

Answer 1

Explanation:

Given that,

Electric field E = 250r V/m

Radius = 20 cm = 0.2 m

We know that,

The electric field is defined as:

E = \dfrac{kq}{r^2}E=

r

2

kq

Where, E = electric field

k = constant

q = charge

r = distance

We substitute the value into the formula

250\times 0.2=\dfrac{9\times10^{9}\times q}{0.2\times 0.2}250×0.2=

0.2×0.2

9×10

9

×q

q = \dfrac{250\times0.2\times (0.2)^2}{9\times10^{9}}q=

9×10

9

250×0.2×(0.2)

2

q=2.22\times10^{-10}\ Cq=2.22×10

−10

C

Hence, The charge will be q=2.22\times10^{-10}\ Cq=2.22×10

−10

C .

Hope it will help you

Answer 2

Answer:

hey above ans is correct mark her brainliest