Question

The electric field in a region of space is [i^+4j^-3k]
KN/C. The electric flux due to this field over an.
area (i^ - j^) m² is​

Answer 1

Explanation:

electric flux is given as the dot product of electric field and the area.

flux = (i+4j-3k)•(i-j)

flux = 1-4 = -3 Nm²/C

negative direction indicates that the flux is acting in the opposite direction

Answer 2

Answer:

The electric flux will be 3 weber

Explanation:

Electric flux is defined as the number of electric field lines passing perpendicular in the given area.

Electric field lines are considered to originate from a positive charge and terminate at a negative charge.

The formula for the same is given below:-

       Ф= E.A

Given

$E=\hat{i}+4\hat{j}+3\hat{k}$

$A=\hat{i}-\hat{j}$

So now putting this value:-

$\phi=(\hat{i}+4\hat{j}+3\hat{k}).(\hat{i}-\hat{j})=-3$

(negative sign indicates the direction of flux)

Therefore the magnitude of flux is 3 weber.