The electric field in
a resion of space is given
al
E = [ 5xî - 2} ] . Potential at point x = 1,y=1
is V1 and potential at point
V2 = (X= 2, y =3) ,then V1-V2 is equal to
Answers
therefore potential difference (v₁ - v₂) is -3.5 volts.
Given : The electric field in a region of space is given as E = [5x i - 2j] . potential at point (1, 1) is v₁ and potential at point (2, 3) is v₂.
To find: potential difference (v₁ - v₂)
solution : we know, ∫dV = -∫E dr
⇒v₁ - v₂ = -∫(5x i - 2j).(dx i + dy j)
⇒v₁ - v₂ = - ∫5x dx + 2∫dy
⇒v₁ - v₂ = - 5[x²/2] + 2[y]
⇒v₁ - v₂ = - 2.5 [2² - 1²] + 2[3 - 1]
⇒v₁ - v₂ = -2.5 × 3 + 4 = -7.5 + 4 = -3.5
therefore potential difference (v₁ - v₂) is -3.5 volts.
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