Question

The electric field in the space between the plate of discharge tube is 3.25×10^-4 NC-¹ . If mass of proton is 1.67×10^-27 kg and it's charge is 1.6×10^-19 C , the force often the proton in the field is
1 . 10.4×10^-15 N
2. 2.0×10^-23 N
3. 5.40×10^-15 N
4. 5.20×10^-15 N

Answer 1

Explanation:

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Answer 2

The force on the proton in the field is 5.2 × 10⁻²³ N

Given,

The electric field (E) in the space between the plate of discharge tube is =  3.25 × 10⁻⁴ NC⁻¹

The mass of the proton is (m) =  1.67 × 10⁻²⁷ Kg

The charge of the photon is (q) =  1.6 × 10⁻¹⁹ C

If a charge of q is placed in an electric field of E, the force on the charge is,

F = qE

∴ According to this,

Force on the proton is,

F = q × E

∴ F = 1.6 × 10⁻¹⁹ × 3.25 × 10⁻⁴  N

⇒ F = 5.2 × 10⁻²³ N

So, the force on the proton is 5.2 × 10⁻²³ N.