The electric field intensity at a point due to point charge is 20 N/C and the electric potential at that point is 10 J/C. Calculate the distance of the point from the charge and magnitude of the charge. (Ans: 0.5, 5x 10 -10 C )
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let the charge = q distance of point from charge q = d
field E = (1/4 πε ) q/ d²
potential V = 1/4 πε) q / d
d = V/E = 10 /.20 = 0.50
q = V * d * (4 πε) = 10 * 0.50 / 9 *10⁹ = 5.55 * 10⁻¹⁰ C
field E = (1/4 πε ) q/ d²
potential V = 1/4 πε) q / d
d = V/E = 10 /.20 = 0.50
q = V * d * (4 πε) = 10 * 0.50 / 9 *10⁹ = 5.55 * 10⁻¹⁰ C
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