Question

The electric field intensity at distance r on the axis of an electric dipole is E1 and E2 on the perpendicular bisector axis of dipole. The angle between E1 and E2 is θ. Will be

Answer 1



1

Secondary SchoolScience5 points

The electric field intensity at distance r on the axis of an electric diople is E1 and E2 on the perpendicular bisector axis of diople the angle between E1 and E2 is ¢ will be

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Ask for details FollowReport byRjchandan1998 02.02.2018

Answers

sivaniantoHelping Hand

let the lenght of the dipole be d. if we rotate the dipole through 90 degrees then it will be come the case of electric feild due to dipole at a point in the equitorial plane. if we consider the vertical componenets at that point in electric field due to dipole(dEsin theta) they will cancel out each other and become zero. so the net electric field will be along the horizontal componenet that is 2dE cos theta. cos theta will be H/B thats is ({d/2}^2 + {r}^2)^ ½ where d/2 is half length of the dipole and r is the distance from the centre of the axis of the dipole. dE= kq/ {d/2}^1/2 + {r}^2  so finally when you multiply the power of {d/2}^2 + {r}^2 will become 3/2 as 1 +1/2 will be 3/2  so your final answer should be dE= kq/ [{d/2}^2 +{r}^2]^3/2.  hope you understood. please correct me if  am wrong. thank you.

Answer 2

The angle between E1 and E2 is 16.

Distance of the electric field = r (Given)

Electric dipole = 1 = E1 (Given)

Electric dipole = 2 = E2 (Given)

When the intensity is Along P -

Eaxis = 2Kp/ r³

When the intensity is Opposite P  

Ebisector = Kp/2r³

= - Kp/ 8r³

Therefore,  

Eaxis/ Ebisector = -2Kp/r³× 8r³/Lp

= 16/1

Ebisector  = - Eaxis/16

Therefore, the angle between E1 and E2 is 16.