Question

the electric field intensity due to a source charge Q at a distance r varies as​

Answer 1

Electric field intensity is force unit charge. it is the strength at a specific point where when we put a charge, it apply force on that charge.

for example, if E is the electric field created by a charge Q at point P which is located at r distance from charge Q. now Let's place a charge q at point P.

then, we observe force experienced by charge q = qE.

from Coulomb's law,

force acts between two charge q and Q = kqQ/r²

so, F = qE = kqQ/r²

so, E = kQ/r²

hence, it is clear that electric field intensity due to a source charge Q at a distance r varies as KQ/r².

Answer 2

Answer:

you can actually remember the formula like this...

F =q x E

Friendly queen Elizabeth...

so, from F = q x E

              E = F/q

we know that F = k Qxq /r^2

--> E = k Qq/r^2 x 1/q

--> E = k Q/ r^2

hope it helps...