Question

`The electric field intensity due to an infinitely long wire having linear charge density= 5 uC/m at a point P asshown in the figure is (OP = 5 m)
1.8x104 N/
C9x10N/C
9x104 N/C
1.8x10 NC`​

Answer 1

Given:

The electric field intensity due to an infinitely long wire having linear charge density= 5 uC/m.

To find:

Field intensity at point P

Calculation:

General expression for Electrostatic Field Intensity at a distance r from infinite wire is as follows:

$\boxed{ \sf{E = \dfrac{2k \lambda}{r} }}$

[Here $\lambda$ is the linear charge density of the wire]

Putting available values in SI unit:

$= > \sf{E = \dfrac{2 \times (9 \times {10}^{9} ) \times ( 5 \times {10}^{ - 6}) }{5} }$

$= > \sf{E = \dfrac{2 \times (9 \times {10}^{9} ) \times ( \cancel{5} \times {10}^{ - 6}) }{ \cancel{5}} }$

$= > \sf{E = 18 \times {10}^{9} \times {10}^{ - 6}}$

$= > \sf{E = 18 \times {10}^{3} }$

$= > \sf{E = 1.8 \times {10}^{4} \: N {C}^{ - 1} }$

So, final answer is:

$\boxed{\rm{E = 1.8 \times {10}^{4} \: N {C}^{ - 1} }}$