Physics, asked by meglamerous, 2 months ago

The electric field just outside a spherical shell of radius R having charge density will be​

Answers

Answered by mitrakshim
18

Answer:

Electric field outside the spherical shell at radial distance r from the center of the spherical shell so that r>R is: E(r>R)=k*Q/r^2 (k is Coulomb's electric constant).

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Answered by muskan007sl
0

Answer:

Electric field just outside a spherical shell will be Kq/r².

Explanation:

In an electrically charged spherical shell the charge lies on the surface of the sphere. Thus, the electric field starts from its surface to outside.

Let us consider a sphere of radius R and the distance of any point just outside the sphere be r such that r > R.

The electric field at this point would be : Kq/r²

where, K = 1/4πε₀ = 9×10⁹Nm²C⁻²

q is the charge on the spherical shell .

#SPJ3

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