Question

The electric field lines due to two charges A and B are as shown in the figure.The ratio of charges on A and B is​

Answer 1

Answer:

electric field directly proportional to chatge

Answer 2

Given:

Electric Field lines due to two charges A and B are provided.

To find:

Ratio of charges on A and B.

Calculation:

The number of electrostatic field lines emitted or terminating on any charge is directly proportional to the magnitude of charge.

$\boxed{ \sf{number \: of \: field \: lines \: \propto \: q}}$

Let's assume that m number of field lines are being emitted from charge A:

$\therefore \: | q_{A}| \: \propto \: m$

Again, let's assume that n number of are terminating on charge B :

$\therefore \: | q_{B}| \: \propto \: n$

Taking the ratio :

$\therefore \: \dfrac{ | q_{A} | }{ | q_{B} | } = \dfrac{m}{n}$

So , final answer is :

$\boxed{ \bold{ \large{ \red{ \: \dfrac{ | q_{A} | }{ | q_{B} | } = \dfrac{m}{n} }}}}$