The electric field lines of forces between two point charges Q1 and Q2 are shown in the figure. Then |Q1/Q2| will be
Answers
Explanation:
The question statement is incomplete as there is no image given also we are not given the charges of Q1 and Q2.
However, if we consider Q1 as positively charged and Q2 as negatively charged, then electric field lines would be from positive to negative charge and f one charge is exerting a force of N newtons on second charge and towards ithe right direction, then the second charge would exert the same force on first one but in opposite direction i.e towards left
Given,
The electric field lines of forces between two point charges Q₁ and Q₂ are shown in the figure.
To find,
the ratio of magnitude of charges Q₁ and Q₂. i.e., |Q₁|/|Q₂|
we know, electric line of force is an imaginary force which represents the strength and direction of electric force at any point.
it means, magnitude of charge is directly proportional to number of lines of forces.
see figure,
number of lines of forces of charge Q₁ = 16
number of lines of force of charge Q₂ = 8
Therefore ratio of magnitude of charge Q₁ and Q₂ is 16 : 8 = 2 : 1.
