The electric field lines of forces between two point charges Q1 and Q2 are shown in the figure. Then |Q1/Q2| will be
Answers
Answer:
ANSWER
E=
4πϵ
o
r
Q
Since, field intensity at point 2 that is at location of Q
2
is −∞.
Hence, Q
2
must be negative and only then for r=0, field at 2 will be −∞.
Now at some distance right of point 2, field is 0.
At that point E=
4πϵ
o
(l+a)
Q
1
+
4πϵ
o
a
Q
2
=0
Since, Q
2
is negative and hence Q
1
must be positive for E to be 0..
Explanation:
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Answer:
Q2 is negative and Q1 is positive
hope it helps you
please marks as brainliest
Explanation:
E=
4πϵ
o
r
Q
Since, field intensity at point 2 that is at location of Q
2
is −∞.
Hence, Q
2
must be negative and only then for r=0, field at 2 will be −∞.
Now at some distance right of point 2, field is 0.
At that point E=
4πϵ
o
(l+a)
Q
1
+
4πϵ
o
a
Q
2
=0
Since, Q
2
is negative and hence Q
1
must be positive for E to be 0..
Answer-(D)