Question

The electric field near two equal and opposite charges place en air at a distance 5cm apart
Mark the direction of the fields lines
Calculate the magnitudenof the charges if the force between them 90N

Answer 1

Answer:

q=5×10"-6

Explanation:

90N=9×10"9×q×q/25×10"-4

10=q×q×10"13/25

250/10"13=q×q

25×10"-12=q×q

q=5×10"-6