the electric field of a light wave is given by E = Eo[i sin (wt-kz). + j sin (wt-kz-π/4)] the polarisation state of the wave is
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Answer:
The electric field of an electromagnetic wave in free space is given by
E
→
=10cos(10
7
t+kx)
j
^
V/m, where t and x are in seconds and metres respectively. It can be inferred that
(i) the wavelength λ is 188.4 m.
(ii) the wave number k is 0.33 rad/m.
(iii) the wave amplitude is 10 V/m.
(iv) the wave is propagating along +x direction.
Which one of the following pairs of statements is correct?
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ANSWER
As given:
E= 10cos(10
7
t+kx)
Comparing it with standard equation of e.m. wave,
E= E
0
cos(ωt+kx)
Amplitude, E
0
=10 V/m
and ω=10
7
rad/s
∵c=vλ=
2π
ωλ
or λ=
ω
2πc
=
10
7
2π×3×10
8
=188.4 m
Also,
c=
k
ω
or k=
c
ω
=
3×10
8
10
7
= 0.033
The wave is propagating along y direction.
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