Question

the electric field potential at a point( x,y) in xy plane is given by v = -kxy, k being a constant; The electric potential intensity at a distance 'r' from the origin is
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Answer 1

Explanation:

partial differntiation

Answer 2

Answer:

Explanation:

V=-kxy

Then,Ex=-dv/dx=-(-ky)=k×0=0 (since accepting to qs,(x,y)=(r,0)

Ey=-dv/dy=kx=kr

Enet=kr

Therefore, E varies directly with r.