Question

The electric flux for Gaussian surface A that enclose the charged particles in free space is
(Given q1 = -14 nC, q2 = 78.85 nC, q3 = – 56 nC)​

Answer 1

We have to find the electric flux for Gaussian surface A that enclose the charge particles in free space.

(Given, q₁ = -14 nC , q₂ = 78.85 nC and q₃ = - 56nC )

Solution : from Gauss’ law, electric flux is the ratio of charge enclosed inside the surface to the permittivity of medium.

i.e., Φ = q/∈₀

see figure, it is clear that total charge enclosed inside the Gaussian surface A = q₁ + q₂ + q₃

= -14nC + 78.85 nC - 56nC

= 8.85 nC

= 8.85 × 10^-9 C

Now, Φ = (8.85 × 10^-9)/(8.85 × 10^-12)

= 10³ Nm²/C

Therefore electric flux for Gaussian surface A is 10³ Nm²/C