The electric flux over the surface of a sphere if it is charged with 10uc is
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We know the electric flux over the surface of a sphere is
Ф=E.A
Or, Ф=E.4πr^2
Or, Ф=Q/ε0;
Where, r= Q/4πε0r^2 and ε0 = permittivity of free space=8.854187817...×10−12 F⋅m−1
Given, Q= 10uC= 10×10^-6 C
So Electric field Ф=Q/ε0
Or, Ф={(10×10^-6)/ε0} v.m
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