Question

The electric flux through the surface(a) in Fig. (iv) is the largest(b) in Fig. (iii) is the least(c) in Fig. (ii) is same as Fig. (iii) but is smaller than Fig. (iv)(d) is the same for all the figures

Answer 1

As per the law of Gauss law of electrostatics, the total electric flux out of a closed surface is equal to the charge enclosed divided by the permittivity.

This can be described as - Ф = Qenclosed/ e0

Therefore the electric flux through a surface does not depend on the shape, area or the size of a surface, whereas it depends on the amount of charge enclosed by the surface.

In the given four figures the charge enclosed is the same which means that the electric flux through all the surfaces should be the same. Hence option (d) - is the same for all figures is correct.

Answer 2

As the net charge enclosed by all the surfaces is same

And, Electric flux (ΦE) 

= Charge enclosed (q)/Permittivity (ε0)

Therefore, correct answer is d)

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