Physics, asked by rahulkumarsingh7397, 1 year ago

The electric flux through the surface vector s equal to 5j in a region of electric field 2i + J is- (a)5 si unit (b)10 si unit (c)11 si unit (d)15 si unit.

Answers

Answered by skymind
23
The electric flux through the surface vector s equal to 5j in a region of electric field 2i + J is- (a)5 si unit (b)10 si unit (c)11 si unit (d)15 si unit.
Answered by mindfulmaisel
0

The electric flux will be (a) 5 S.I. unit.

Given, the electric field = 2i + j

          the surface vector = 5j

We know, the electric flux through a surface is perpendicular to its surface area and parallel or along the line of the surface area vector provided condition, an electric field is present in that region.

So, the electric flux would be the dot product of the electric field and the surface area vector.

so, here, the electric flux will be = (2i + j) . (5j)

                                                     = 5 S.I. unit [ As, j.j = 1 and i.j = 0]

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