Question

The electric force between two charged objects is .18 Newtons. What will be the new electric force if the objects are moved three times further apart?

Answer 1

Answer:

0.06 newton

Explanation:

F= 0.18 N= $\frac{kq_{1}q_{2} }{r^{2} }$--->a

F'= $\frac{kq_{1} q_{2} }{r'^{2} }$ --->b

r'= 3r--->c

Putting c in b,

F'=1/3($\frac{kq_{1}q_{2} }{r^{2} }$)--->d

Putting a in d,

F'=F/3=0.18/3=0.06N

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