The electric force between two electric charges at distance r is F1. If the value of each electric charge is
doubled and distance between them is halved then force is F2, then F1 / F2 ________
(A) 16: 1 (B) 1: 16 (C) 8:1 (D) 1: 8
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The force between the two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Hence, if distance between charges is halved (charges remaining kept constant), the force between the two charges is quadrupled.
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