Question

The electric potential at a point, due to a positive charge of 100 C distance of 9 m, is

(a) 104 V (b) 106 V (c) 105 V (d) 107 V​

Answer 1

Given:

Charge of 100 $\mu C$ has been provided.

To find:

Electric Potential at 9 m from charge ?

Solution:

The general expression for electric potential is:

$\therefore V = \dfrac{kq}{r}$

• 'k' is Coulomb's Constant, 'q' is charge and 'r' is distance.

$\implies V = \dfrac{(9 \times {10}^{9} )\times 100 \times 10^{-6}}{9}$

$\implies V = {10}^{5} \: volts$

So, field potential is 10⁵ Volts.