The electric potential at a point in free space
due to a charge Q coulomb is Q1011 volts.
The electric field at that point is
(a) 47, Qx1022 volt/m
(b) 12 TE, Qx1020 volt/m
(c) 4 ne, Qx1020 volt/m
(d) 12 n£, Qx 1022 volt/m
Answers
Answered by
1
Answer:
The answers is.( D )this is write answers
Answered by
6
Answer:
(C)
Explanation:
V=KQ/R
Q×10∧11=KQ/R
R=K/10∧11
PUT THIS VALUE IN EQUATION OF E
E=KQ/R∧2
E= 4π∈Q×10∧22
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