The electric potential at a point (x, 0, 0) is given by
V =[1000/x+1500/x^2+ 500/x^3]
*
then the electric field at x =1 m is (in volt/m):
(A) -5500i^
(B) 5500i^
(C) √5500i^
(D) zero
Answers
Answered by
0
Explanation:
V=(
x
1000
+
x
2
1500
+
x
3
500
)
We know that, E=
dr
−dv
So,
E=
dx
−d(
x
1000
+
x
2
1500
+
x
3
500
)
at x=1
=−[
x
2
(−1000)
−
x
3
2×1500
−
x
4
3×500
]
x=1
=1000+3000+1500=5500V/m
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