The electric potential at point A is 1
V and at another point B is 5V. A
charge 3uC is released from B.
What will be the kinetic energy of
the charge as it passes through A?
1. 8x 10-J
2. 12 x 10- J
3.12 x 10-6J
4. 4x 10J
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Answer:
When the charge is released to move freely, thework done by electric field is equal to change in kinetic energy
∴WEF=ΔKE −qΔV=ΔKE
KE=−3×10−6(1−5)=12×10−6J
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