The electric potential at point A is 20 V and at B is -40 V. Find the work done by an external and electrostatic force in moving an electron slowly from B to A.
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1
Answer:
w = vQ
Q = It
so , Q= 1.6 ×10^8
w = -60 × 1.6 × 10^8
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The work done by an external and electrostatic force in moving an electron slowly from B to A is :
• Given : Electric potential at point A is 20 V and at B is -40 V, charge on electron = 1.6×10^-19 C
• For work done by external force,
Wex = q×( Vb - Va )
= q×(-40-20)
= -1.6×10^-19×60
= -96×10^-19 J
• For work done by electrostatic force,
Wes = q×( Va - Vb )
= q×( 20 + 40 )
= q×60
= 1.6×10^-19×60
= 96×10^-19J
• Hence, Wex = -Wes
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