The electric potential at the 2 ends of conductor are 10 V and 5 V respectively.
5 J of work needs to be done to move certain amount of charge from the end at the higher potential to lower potential. Find the amount of charge moved..??
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Hey there,
According to this formula
V = 10 - 5
= 5v
W = 5 J
Q = V×W
Q = 5×5
Q = 25 C
HOPE YOU GOT IT
PLS MARK IT AS BRAINLIST
According to this formula
V = 10 - 5
= 5v
W = 5 J
Q = V×W
Q = 5×5
Q = 25 C
HOPE YOU GOT IT
PLS MARK IT AS BRAINLIST
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