The electric potential at the surface of charged solid is 20 volt.Find the electric potential at its centre .
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so the answer is 20 volt
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Using Gauss' law, the electric field inside the sphere is:
E=k
r
2
(Qr
3
/R
3
)
=kQr/R
3
, where k=1/4πϵ
o
.
Thus, inside sphere, electric field varies linearly with r.
Now if potential at the surface is V then electric field is Vr/R
2
. So It should be V/2R if distance from the center is R/2.
Thus, both assertion and reason are true but reason is not the correct explanation of the assertion.
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