Question

The electric potential due to a dipole molecule of a electric dipole moment 6*10-30 A

Answer 1

Explanation:

Step 1: Dipole moment

Dipole moment of dipole is given as:

P=q×ℓ

P=6×10 ^−3C×0.1 m=6×10^−4Cm

Step 2: Magnitude of electric field

Torque on a dipole in an electric filed is given by:

τ= P× E

⇒τ=PEsinθ,

where θ is the angle between dipole and electric field.

⇒6 √3=6×10 ^−4×E×sin30∘

⇒E=[(6√3×2)÷ (6×10 ^−4×1)]=2 √3×10 ^4N/C

Step 3: Potential energy of dipole

Potential energy of a dipole in an electric filed is given by:

U=− P. E

⇒U=−PEcosθ=−6×10 −4×2 √3×10 ^4×cos30∘

=−18 J

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