Physics, asked by kanchansingh6821, 1 year ago

The electric potential due to a small electric dipole at a large distance r from the centre of the dipole is proportional to(a) r(b) \frac{1}{r}(c) \frac{1}{r^{2}}(d) \frac{1}{r^{3}}

Answers

Answered by darshilgalaiya
0

Option B

 \frac{1}{r}

Answered by Anonymous
0

Answer:

1/r²

Explanation:

An electric dipole is an arrangement where two equal and opposite charges are separated by a small distance. Electric potential due to dipole at a point away from the dipole is represented by the equation -

V=(1/4πε₀) Pcosθ/r²

Since, electric potential is inversely proportional to r²

Hence. V α 1/r²

Electric potential due to a small electric dipole at a large distance r from the center of the dipole is always proportional to 1/r². Therefore, the electric potential due to a small electric dipole at a large distance r from the center of the dipole is proportional to 1/r²

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