Question

the electric potential is V=(x^2-2x).what is the electric field strength at x=1?
pls answer.. ​

Answer 1

E = -dV/dx = -d(x^2-2x)/dx = 2-2x

So,

E = 2-2(1) = 0 Newton/Coulomb at x = 1 for given equation of potential

Hope this helps you !

Answer 2

Heya!!

E = -dv/dx

Here v = x² - 2x

=>

-E = d(x² - 2x )/dx

=>

-E = 2x - 2

E at x = 1 is

-E = 2 ( 1 ) - 2

=>

E = 0 N/c