Question

the electric potential on the surface of a sphere of radius R and charge 3 x 10^-6 C is 500V then find the electric field intensity on the surface of the sphere​

Answer 1

Answer ⇒ E = 9.26 N/C.

Explanation ⇒

Using the formula,

Potential = kQ/R

∴ 500 = 9 × 10⁹ × 3 × 10⁻⁶/R

∴ R = 27 × 1000/500

∴ R = 54 m.

Now, Electric field = Potential/Radius [For sphere.]

∴ E = 500/54

∴ E = 9.26 N/C.

Hope it helps.