Question

The Electric Potential V as A Function Of Distance x (in meter) Given By
V = (5x² + 10 x - 9) Volt
The Magnitude Of Electric Field at x = 1 m is

Give answer with explanation ✔️
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Answer 1

$\huge \underbrace \mathfrak \red{⛄Answer࿐⛄}$

We know, E=− dx/dv

V=5x

2

−10x−9

dx

dV

=10x−10

so, E=−(10x−10)

For x=1m, the value of E=−(10−10)=0V/m

Answer 2

Answer:

$We \: know, E= \frac{ - dv}{dx}$

$= > V= {5x}^{2} −10x−9$

$= > \frac{dV}{dx} =10x−10$

so, E= −(10x−10)

For x = 1m, the value of E= −(10−10)= 0V/m