The electric potential V at any point in space os given V= 20x3 Volt, where x is in meter. Calculate the electric intensiity at point P (1,0,2)
Answers
Answer:
we know that the following relation exists between electric field (E) and potential (V)
E = -dV/dx
here
V = 20x3 volts
so,
E = d(20x3)/dx
or
E = 60x2
here
x = 1
thus,
E = 60.(1)2 = 60 N/C
Explanation:
The electrical potential (also known as the electric field capacity, ability drop, the electrostatic capacity) is defined as the quantity of work electricity needed to flow a unit of electric rate from a reference factor to the specific factor in an electric subject. more precisely, it's far the power in keeping with unit charge for a check price that is so small that the disturbance of the field under consideration is negligible. moreover, the movement across the field is supposed to continue with negligible acceleration, as a way to keep away from the take a look at charge obtaining kinetic electricity or generating radiation. by way of definition, the electrical ability on the reference point is zero units. typically, the reference point is earth or a point at infinity, although any factor may be used.
In classical electrostatics, the electrostatic subject is a vector quantity this is expressed because the gradient of the electrostatic potential, which is a scalar quantity denoted by way of V or sometimes φ,[1] equal to the electric potential power of any charged particle at any location (measured in joules) divided through the charge of that particle (measured in coulombs). via dividing out the price on the particle a quotient is received that is a belongings of the electric discipline itself. In quick, an electric ability is the electric capability electricity in step with unit rate.
The electric potential V at any point in space os given V= 20x3 Volt, where x is in meter.
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