Question

The electric potential V (in volt) varies with X (in
metre) according to the relation V = 5+4x^2.The
force experienced by a negative charge of 2 x 10-6
C located at x = 0.5 m is
(A)2 ×10-6N
(B) 4 x 10-6N
(C) 6 x 106N
(D) 8 x 10-6N​

Answer 1

answer : option (4) 8 × 10^-6 N

explanation : electric field is the rate of change of electrical potential with respect to position.

e.g., |E| = dV/dx

so, differentiating given expression V = 5 + 4x² with respect to x , To find electric field intensity.

so, |E| = dV/dx = 8x

at x = 0.5m

|E| = 8 × 0.5 = 4N/C

given, magnitude of charge , q = 2 × 10^-6 C

now, force = electric field intensity × charge

= |E| × q

= 4 N/C × 2 × 10^-6 C

= 8 × 10^-6 N

hence, force experienced by charge is 8 × 10^-6 N

Answer 2

Answer:

hi

i have attached the answer

hope it helps.....