Physics, asked by avadhutdaule853, 10 months ago

The electric potential V is
given as a function of
distance x (metre) by
V =(5x² +10x–9) volt.
Magnitude of electric field
at x = 1 is​

Answers

Answered by sbtgta125
0

Answer:

Magnitude of electric field in such conditions at x = 1m is 30 N/C

Explanation:

E = -dV/dx

E = -(10x+10)

Putting values of x=1

E = -30 N/C

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