The electric potential V is
given as a function of
distance x (metre) by
V =(5x² +10x–9) volt.
Magnitude of electric field
at x = 1 is
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Answer:
Magnitude of electric field in such conditions at x = 1m is 30 N/C
Explanation:
E = -dV/dx
E = -(10x+10)
Putting values of x=1
E = -30 N/C
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