The electric resistance of a certain wire of iron is R if it's length and radius are both doubled then what will be the new resistance
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Answer:
The electric resistance of a certain wire of iron is R, if it's length and radius are both doubled then the new resistance will be the half of the previous resistance .
Explanation:
We know that,
R1 = ρl1/A1
Where R1 = current resistance of the wire.
l1 =current length of the wire.
A1 =(πr²) current cross-sectional area of the wire.
When the length and the radius are both doubled then,
A2 = π(2r)² = 4πr² = 4A1
l2 = 2l1
Let the new resistence be R2.
So,
R1/R2 = (ρl1/A1) / (ρl2/A2)
= (ρl1/A1) / (2ρl1/4A1)
= 2
R2 = R1/2.
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