The electrical capacity of a parallel plate capacitor is 20 mF.If the space between the two plates is
completely filled with a dielectric medium the capacity increases to 45 mF. Find the dielectric constant of material medium
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Answer:
Explanation:
Capacitance of capacitor C=20μF
=20×10 −6 F
Rate of change of potential is, DV/DT=3v/s
q=CV
DQ/DT=c(DV/DT)
ie
=20×10−6 ×3
=60×10 −6 A
=60μA
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