Chemistry, asked by pritamsuklabaidya741, 9 hours ago

the electrical cell a and b containing znso4 and CUs o4 solution respectively are connected in series on passing certain amount of electricity 15.2g of zinc was deposited in cell a how much copper would be deposited in cell​

Answers

Answered by sanskarsgirawale
0

Answer:

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0.426g of copper

Explanation:

Cell B: Ag

+

+e

⇌Ag at cathode.

1 mole (108 g) of Ag is deposited by 96500 C.

1.45 g of Ag will be deposited by

108

96500×1.45

=1295.6C.

Now,

Q=It

1295.6=1.5×t

t=864s

Cell A: Zn

2+

+2e

→Zn

2 moles of electrons (2×96500 C of current) produces 1 mole (63.5 g) of zinc.

1295.6 C of electricity will deposit

2×96500

65.3

×1295.6=0.438 g of zinc

Cell C: Cu

2+

+2e

→Cu

2 moles of electrons (2×96500 C) of current will produce 1 mole (63.5 g) of Cu.

1295.6 C of current will deposit

2×96500

63.5×1295.6

=0.426g of copper

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