Question

The electrical resistance of a coloumn of 0.05 M NaOH solution of diameter 1 cm and length 50 cm is 5550 ohm . Calculate its resistivity, conductivity, and molar conductivity.

Answer 1

R = ρ L / A                cell constant = L / A
ρ = resistivity = Resistance / cell constant 
    = 5550 Ω* π 0.005² m² / 0.50 m = 0.871 Ω-m
Conductivity σ = 1/ρ = 1.147 mho/m

Molar conductivity = σ/M = 1.147/0.05 = 22.94 mho/m/mole