Physics, asked by doreamon641, 7 hours ago

The electrical resistivity of copper at 27 degree Celsius is 1.72 x 10^(-8) ohm meter.compute its thermal conductivity if the Lorentz number is 2.26 x 10 ^(-8) watts ohm per levin square​

Answers

Answered by Ayushiprogod1000
0

Answer:

Alan Turing: father of the modern

computer.

Answered by rahul123437
0

The thermal conductivity is 2.14*10^-19

Explanation:

Given :

electric resistivity of a copper = 27

R = 1.72 x 10^-8 ohm meter

Lorentz number = 2.26 x 10 ^-8 watts ohm per levin square​

The Lorentz number is a dimensionless number that relates the thermal conductivity of a metal to its temperature and its electrical conductivity. The Lorentz number equals voltage squared times specific electrical conductivity divided by the temperature difference and specific thermal conductivity.

f= m/en^2\pi

\pi =m/ne^2*f

= 9.11*10^-31/8.4*10^28*1.7*10^-8*(1.6*^-19)^2

= 2.14*10^-19

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