The electrical resistivity of silver is 1.6×10-8 Ωm what will be resistance of a silver wire of length 1 cm.
and cross sectional area 2×10-3m
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Answer:
8 × 10^-8 ohm
Explanation:
According to the given question,
p = resistivity = 1.6×10^-8 ohm.m
l = length = 1 cm = 10^-2 m
A = Area of cross section = 2×10^-3 m^2
R = Resistance
And we are asked to find the resistance.
We know,
- R = pl/A
Putting the values we get,
- R = (1.6×10^-8 ×10^-2)/2×10^-3
- R = 1.6 × 10^-10/2×10^-3
- R = 16 × 10^-11/2×10^-3
- R = 8 × 10^-8 ohm
Thus resistance of the silver wire is 8×10^-8 ohm.
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