Question

The electricity in Faradey to 2 points require for converting 1 mole of CaCl2 is​

Answer 1

Answer:

Answer

O.5 Faraday.

Explanation :-

The reaction that takes place is :-

Hence, 2 moles of electron is required to obtain one mole of Ca.

Here, Number of moles of Ca = 10/40 = 1/4 ( Since,molar mass of C = 40 gram.

For 1 mole ----------- 2 moles of electron are required

For 1/4 mole --------- 1/2 mole of electron is required.

Now, 1 mole of electronic charge = 1 Faraday = 1 F

Hence, 1/2 moles of electronic charge = 1/2 = 0.5 Faraday.

Additional details

96,475 C of charge = 1 Faraday = Charge on one mole of electron but we take 96,475 as 96,500 C.

Explanation:

hope it will help u

Answer 2

Answer:

(1) Ca

2+

+2e

−

→Ca

1 mole (40 g) of Ca will require 2 F of electricity.

20 g (0.5 mole) of Ca will require 1 F of electricity.

(2) Al

3+

+3e

−

→Al

1 mole (27 g) of Al will require 3 moles of electrons.

40 g of Al will require

3×40F=4.4 F